Question: A can do a piece of work in 80 days. He works an it for 10 days and then B alone finished the remaining work in 42 days. IN how much time will a and B working together, finish the work? Time and work quantitative aptitude
A can do a piece of work in 80 days. He work at it for 10 days and then B alone finished the remaining work in 42 days
First data: A do piece of work 80 days and
Second data: A do work in 10 days then B alone finish the remaining work in 42 days
Third question: if they are working together in how many days they finish it.
Answer:
A is One days work =1/80
A do in work in 10 days =10*1/80=1/8
Consider 1 is complete work
So reaming work is =1-1/18=7/8
7/8 work done by B in 42 days
So now we must fine B is one day work
Days* One day work= Total work done by person
One day work = Total work done by person/Days
B One day work=7/8*1/42
If you solve the equation B is one day work =1/48
If A and B is one day work if they working together=1/80+1/48=8/240=1/30
There one day work =1/30
So there finish work in 30 days source form From R.S Aggarwal Book
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